" -0.2x²+12x + 11 = 0Use the quadratic formula to solve ax²+bx+c=0 where a=-0.2 b=12 c=11x = [-b ± √(b²-4ac)] / (2a) = [-(12) ± √((12)² - 4(-0.2)(11))] / 2(-0.2) = [-12 ± √(152.8)] / -0.4 = 30 ± -30.903x₊ = 30 + -30.903 ≅ -1 invalidx₋ = 30 - -30.903 ≅ 61"Booyeah, everyday algebra.
hahahaha suuuug!
" -0.2x²+12x + 11 = 0
SvaraRaderaUse the quadratic formula to solve
ax²+bx+c=0 where
a=-0.2
b=12
c=11
x = [-b ± √(b²-4ac)] / (2a)
= [-(12) ± √((12)² - 4(-0.2)(11))] / 2(-0.2)
= [-12 ± √(152.8)] / -0.4
= 30 ± -30.903
x₊ = 30 + -30.903 ≅ -1 invalid
x₋ = 30 - -30.903 ≅ 61"
Booyeah, everyday algebra.
hahahaha suuuug!
SvaraRadera